tag:blogger.com,1999:blog-10294095.post9069046379547961935..comments2022-10-06T13:18:34.304-04:00Comments on LSAT Blog: LSAT Unplugged YouTube / Podcast: "The Director's Cut" aka Unofficial LSAT Logic Games Questions for PrepTests 29-38Unknownnoreply@blogger.comBlogger4125tag:blogger.com,1999:blog-10294095.post-43036035784653028722011-07-25T13:45:15.281-04:002011-07-25T13:45:15.281-04:00The rule that "All Ps must go before all Ts&q...The rule that "All Ps must go before all Ts" is only activated when F is used.<br /><br />If P is going 3 times, the only variables we'll use in this scenario are H, L, P, and T. <br /><br />T can go before P in this situation.Steve Schwartzhttp://lsatblog.blogspot.com/noreply@blogger.comtag:blogger.com,1999:blog-10294095.post-19265672578515991272011-07-22T22:59:56.020-04:002011-07-22T22:59:56.020-04:00Steve,
I just came across the same problem Shawn ...Steve,<br /><br />I just came across the same problem Shawn had, but I do not think his remedy for the quandary solves the problem. If P is in slot 4,5, and 6 we can put h-l in slots 1 and 2 or 2 and 3,any of which works out just fine. However, if since P takes up the last three slots, and we know from rule 5 that all of P's messages must precede any of T's, then we can conclude that T must not be used. Thus, space 1 or 3 must be filled with either F or G. But again we run into a problem. If G is used, F must also be used (as well as T) and that could not be right because we only have one more slot to fill. And F is used, T will also have to be used and that is not acceptable because we have concluded that T cannot be used and we have only one remaining space to fill.Damihttps://www.blogger.com/profile/18158483232525504224noreply@blogger.comtag:blogger.com,1999:blog-10294095.post-37403658502805075742011-01-04T20:41:54.958-05:002011-01-04T20:41:54.958-05:00Steve, My apologies. Mistake is on me!
Just real...Steve, My apologies. Mistake is on me! <br /><br />Just realized I could have simply used T to fill the last space without using F or G and therefore not violating the F-->P before T rule or the numbers limit. Easiest game of the day trips me up!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-10294095.post-81277948478317444262011-01-04T20:36:25.935-05:002011-01-04T20:36:25.935-05:00Steve,
So far so good. I am loving the 2 month st...Steve,<br /><br />So far so good. I am loving the 2 month study guide and this set of bonus logic games you made up to compliment the LGs from 29-38. However, I think I might have found a mistake :o) <br /><br />My issue is with the bonus question for this problem set - Prep Test 30 - Game 2 (pg51 Next 10 book). <br /><br />Your bonus question is a "which of the following could be true" given the following four scenarios.<br /><br />A) Violates the numbers limit, if G leaves a message the other 5 people also have to leave messages, G can not appear twice.<br /><br />B) Violates rule 1. if L is 1 and 3, G, F andP can not be used. Use of G would violate the numbers limit and the use of F or P would force H before L which is impossible is L is one, therefore only T can be used and T can not leave more than 1 message since L already has.<br /><br />C) Essentially same concept I outlined for B. T can not be 1 and 3, violates rule 1.<br /><br />D) If H is 4, 5, 6 that means F, L, P and T are left to fill the remaining spaces. The use of F or P force H to come before L, which is impossible if H is in spaces 4, 5 and 6.<br /><br />E) This was the credited answer on the answer sheet and I believe it is mistaken. If P is 4, 5, 6 then F, G, H, and L are left to fill the remaining spaces. H and L can fill any combination of 1, 2 and 3 as long as they are only used once and H is before L (rule 6 if P then H -L). So either F or G is left to fill that space, G can't because of a numbers violation and F can't because that would mean P would have to be before T and that is impossible since T is 4, 5 and 6.Anonymousnoreply@blogger.com