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Here's a Logic Games question from the June 2004 LSAT.
Let's re-use a diagram from a previous question (the others aren't helpful):
X: T I F H
Y: F H S
Z: T I P H
We can eliminate A, B, and E because this correct diagram contradicts them. C and D remain, so we'll first work on C.
Let's think about the rules to see whether or not we can eliminate more choices. The first 2 rules say F serves Y and F serves 2 buildings (one of X and Z is among those two). F and P can't go together (second to last rule), so P can't go to both X and Z (since F will be at one of them). P couldn't go with X and Z, so C is correct.
Remember:
Re-use diagrams and think about the rules to eliminate choices rather than drawing new diagrams, whenever possible.
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