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Here's a Logic Games question from the October 1996 LSAT.
Let's think about the rules and apply them before diagramming. The first rule yields nothing. The second rule says that if N is reduced, R and S can't be. C would violate that rule, so C is out. The next rule doesn't help. However, the last is very helpful, in conjunction with the one before it. It says that out of LMR, two must be reduced. If P is chosen, as in this question, L can't be reduced, the preceding rule says. So if three of LMR must be reduced, and L can't be, M and R must be. So we know B is correct.
Remember:
Think about the rules and try to apply them before diagramming. Of course, if after about 30 seconds, you aren't able to make any inferences, go ahead and diagram.
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